Sorry, but with the World Series on, I couldn’t resist.
Now, to my question before this august group. If I build a wye, using a #6 commercial frog as the starting point, will I then have a #3, or #6 wye? The answers, of course, won’t change anything, in the great scheme of things, but it will help me to sleep at night.
If you use a #6 frog, and position it evenly, so each leg diverts at the same rate, then each leg will be diverting as if they came from a #12 switch.
But since the different legs will be diverging the same rate as they would from a number 6 switch, I guess it would be a number 6 Wye.
David Maynard said:
If you use a #6 frog, and position it evenly, so each leg diverts at the same rate, then each leg will be diverting as if they came from a #12 switch.
But since the different legs will be diverging the same rate as they would from a number 6 switch, I guess it would be a number 6 Wye.
David,
As I understand the frog number system…the #6 is the ratio of divergence. Therefore 1 in 6. That is NOT a variable. To get a #12 switch to divert as a #12, you have to use a #12 frog. You are correct that a #6 frog on a wye or any other switch with a #6 frog is STILL a #6.
Steve,
As to your question: A #3 frog will give you a #3 wye.A #6 frog will give you a #6 wye.
I used Sunset Valley switches on my layout and they are engineered and built the same as the prototype. I used a #4 WYE (14 degree, 1 in 4 with a 90 inch radius) and #6 left/right switches (9.5 degree, 1 in 6 with a 90 inch radius). My purpose was to hold to a 90 inch radius MINIMUM on the layout. Radii was more important to me than the frog number.
Hope this helps :).
A #6 wye is #6 divergence on both routes… a #6 switch is straight on one side and #6 divergence on the other.
#6 means a 1 in 6 divergence vs. travel… go 6 inches and it should diverge 1 inch.
This pictures on this page will be pretty self-explanatory:
Greg
Because the ‘action’ of the frog is doubled it might seem that it is a different #. Yet, as Gary pointed out, it’s the divergence that determines the #.
Now to continue the banter, the Wye frog should be confused with a #3, not the other way, just because of the doubled divergence in that track configuration. (http://www.largescalecentral.com/externals/tinymce/plugins/emoticons/img/smiley-wink.gif)More (d)in fewer feet (run)…
Happy Rails,
John
So, after all this, a #6 frog yields a #6 wye. Correct?
Gary Armitstead said:
David Maynard said:
If you use a #6 frog, and position it evenly, so each leg diverts at the same rate, then each leg will be diverting as if they came from a #12 switch.
But since the different legs will be diverging the same rate as they would from a number 6 switch, I guess it would be a number 6 Wye.
David,
As I understand the frog number system…the #6 is the ratio of divergence. Therefore 1 in 6. That is NOT a variable. To get a #12 switch to divert as a #12, you have to use a #12 frog. You are correct that a #6 frog on a wye or any other switch with a #6 frog is STILL a #6.
Yes, the divergence from each leg of the switch is a number 6. 1 unit of separation for 6 units of travel. I agree, that is fixed. What I am saying is that since both legs diverge, each leg diverges from a straight path at half the angle. So, each leg diverges from a straight path the same amount as a number 12 switch.
Now, yer jes trying’ to cornfuse me, aintcha.
Steve Featherkile said:
Now, yer jes trying’ to cornfuse me, aintcha.
But of course. Have I succeeded?
Is Devon involved with this question ?..!!
the answer should be simple.
imaging a right No 6 layed on top a left No 6. = two desviations of “6” each. (together a No 3 desviation)
imaging a right No 12 layed on top a left No 12. = two desviations of “12” each. (together a No 6 desviation)
and, for sure, a wye-frog needs to “desviate” to both sides. = has to be double as wide, than a frog of a “normal” switch.
Korm yes, but the question was based on using a number 6 frog, so its a number 6 Wye. I was just explaining the track would not diverge from the center-line of the straight track as fast as a “regular” number 6’s diverging track would diverge.
A frog is a frog is a frog…regardless of the track work it is used in.
This was gleaned from http://www.ltrc.lsu.edu/ltc_13/pdf/presentations/S38_Railroad%20Engineering%20101_LTC2013.pdf
Jeeze… I think I see what Steve is asking.
If you used the frog from a #6 Wye in a regular switch, you would have a #3 switch… is that what you are asking Steve?
Indeed, the frog removed from a #6 wye will measure a 1 in 3 divergence, just like my picture showed in the link… I thought the picture in my link would have helped.
Greg
Nice photo at the bottom of this page. All you need to know.
Now, to my question before this august group. If I build a wye, using a #6 commercial frog as the starting point, will I then have a #3, or #6 wye?
It doesn’t matter what kind of switch it is. A #6 frog makes a #6 switch. What the rails do after that has nothing to do with the frog.
Ken, my friend; you are oh so correct, but as as others who have made basically the same statement have found; a bunch of people can’t seem to understand the statement, and basically can’t comprehend what a #6 frog is, and what a certain switch, wye or otherwise is, when designed as a #6 switch.
Fred Mills
Fred Mills said:
Is Devon involved with this question ?..!!
How did I get brought into this?
